Solve (3y-5)+(2y-8)=?

$$( 3 y - 5 ) + ( 2 y - 8 ) = ?$$

Evaluate

$$5y-13$$

Solution Steps

Combine 3y and 2y to get 5y.

$$5y-5-8$$

Subtract 8 from -5 to get -13.

$$5y-13$$

Differentiate w.r.t. y

$$5$$

Steps Using Derivative Rule for Sum

Combine 3y and 2y to get 5y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(5y-5-8)$$

Subtract 8 from -5 to get -13.

$$\frac{\mathrm{d}}{\mathrm{d}y}(5y-13)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$5y^{1-1}$$

Subtract 1 from 1.

$$5y^{0}$$

For any term t except 0, t^{0}=1.

$$5\times 1$$

For any term t, t\times 1=t and 1t=t.

$$5$$