Solve (3y+6)+(-2y-4)=

$$( 3 y + 6 ) + ( - 2 y - 4 ) =$$

Evaluate

$$y+2$$

Solution Steps

Combine 3y and -2y to get y.

$$y+6-4$$

Subtract 4 from 6 to get 2.

$$y+2$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

Combine 3y and -2y to get y.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y+6-4)$$

Subtract 4 from 6 to get 2.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y+2)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$