Solve (3x-5)(2x+1)=6x^2-5x+15

$$( 3 x - 5 ) ( 2 x + 1 ) = 6 x ^ { 2 } - 5 x + 15$$

Solve for x

$$x=-10$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3x-5 by 2x+1 and combine like terms.

$$6x^{2}-7x-5=6x^{2}-5x+15$$

Subtract 6x^{2} from both sides.

$$6x^{2}-7x-5-6x^{2}=-5x+15$$

Combine 6x^{2} and -6x^{2} to get 0.

$$-7x-5=-5x+15$$

Add 5x to both sides.

$$-7x-5+5x=15$$

Combine -7x and 5x to get -2x.

$$-2x-5=15$$

Add 5 to both sides.

$$-2x=15+5$$

Add 15 and 5 to get 20.

$$-2x=20$$

Divide both sides by -2.

$$x=\frac{20}{-2}$$

Divide 20 by -2 to get -10.

$$x=-10$$