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\left(3x-2\right)^{2}-18+18=18
Add 18 to both sides of the equation.
\left(3x-2\right)^{2}=18
Subtracting 18 from itself leaves 0.
3x-2=3\sqrt{2} 3x-2=-3\sqrt{2}
Take the square root of both sides of the equation.
3x-2-\left(-2\right)=3\sqrt{2}-\left(-2\right) 3x-2-\left(-2\right)=-3\sqrt{2}-\left(-2\right)
Add 2 to both sides of the equation.
3x=3\sqrt{2}-\left(-2\right) 3x=-3\sqrt{2}-\left(-2\right)
Subtracting -2 from itself leaves 0.
3x=3\sqrt{2}+2
Subtract -2 from 3\sqrt{2}.
3x=2-3\sqrt{2}
Subtract -2 from -3\sqrt{2}.
\frac{3x}{3}=\frac{3\sqrt{2}+2}{3} \frac{3x}{3}=\frac{2-3\sqrt{2}}{3}
Divide both sides by 3.
x=\frac{3\sqrt{2}+2}{3} x=\frac{2-3\sqrt{2}}{3}
Dividing by 3 undoes the multiplication by 3.
x=\sqrt{2}+\frac{2}{3}
Divide 3\sqrt{2}+2 by 3.
x=\frac{2}{3}-\sqrt{2}
Divide -3\sqrt{2}+2 by 3.
x=\sqrt{2}+\frac{2}{3} x=\frac{2}{3}-\sqrt{2}
The equation is now solved.