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3x-1=\sqrt{5} 3x-1=-\sqrt{5}
Take the square root of both sides of the equation.
3x-1-\left(-1\right)=\sqrt{5}-\left(-1\right) 3x-1-\left(-1\right)=-\sqrt{5}-\left(-1\right)
Add 1 to both sides of the equation.
3x=\sqrt{5}-\left(-1\right) 3x=-\sqrt{5}-\left(-1\right)
Subtracting -1 from itself leaves 0.
3x=\sqrt{5}+1
Subtract -1 from \sqrt{5}.
3x=1-\sqrt{5}
Subtract -1 from -\sqrt{5}.
\frac{3x}{3}=\frac{\sqrt{5}+1}{3} \frac{3x}{3}=\frac{1-\sqrt{5}}{3}
Divide both sides by 3.
x=\frac{\sqrt{5}+1}{3} x=\frac{1-\sqrt{5}}{3}
Dividing by 3 undoes the multiplication by 3.