Solve (3x^2-2x-1)-(2x^2-8x-5)=x^2-7

$$( 3 x ^ { 2 } - 2 x - 1 ) - ( 2 x ^ { 2 } - 8 x - 5 ) = x ^ { 2 } - 7$$

Solve for x

$$x = -\frac{11}{6} = -1\frac{5}{6} \approx -1.833333333$$

Steps for Solving Linear Equation

To find the opposite of 2x^{2}-8x-5, find the opposite of each term.

$$3x^{2}-2x-1-2x^{2}+8x+5=x^{2}-7$$

Combine 3x^{2} and -2x^{2} to get x^{2}.

$$x^{2}-2x-1+8x+5=x^{2}-7$$

Combine -2x and 8x to get 6x.

$$x^{2}+6x-1+5=x^{2}-7$$

Add -1 and 5 to get 4.

$$x^{2}+6x+4=x^{2}-7$$

Subtract x^{2} from both sides.

$$x^{2}+6x+4-x^{2}=-7$$

Combine x^{2} and -x^{2} to get 0.

$$6x+4=-7$$

Subtract 4 from both sides.

$$6x=-7-4$$

Subtract 4 from -7 to get -11.

$$6x=-11$$

Divide both sides by 6.

$$x=\frac{-11}{6}$$

Fraction \frac{-11}{6} can be rewritten as -\frac{11}{6} by extracting the negative sign.

$$x=-\frac{11}{6}$$