Solve for y
y=\left(3x+2\right)^{2}
Solve for x (complex solution)
x=\frac{-\sqrt{y}-2}{3}
x=\frac{\sqrt{y}-2}{3}
Solve for x
x=\frac{-\sqrt{y}-2}{3}
x=\frac{\sqrt{y}-2}{3}\text{, }y\geq 0
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9x^{2}+12x+4=y
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3x+2\right)^{2}.
y=9x^{2}+12x+4
Swap sides so that all variable terms are on the left hand side.
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