Solve (3-p)+[5-4r+2(6div5p)]

$$( 3 - p ) + [ 5 - 4 r + 2 ( 6 \div 5 p ) ]$$

Evaluate

$$\frac{7p}{5}-4r+8$$

Solution Steps

Add 3 and 5 to get 8.

$$8-p-4r+2\times \frac{6}{5}p$$

Express 2\times \frac{6}{5} as a single fraction.

$$8-p-4r+\frac{2\times 6}{5}p$$

Multiply 2 and 6 to get 12.

$$8-p-4r+\frac{12}{5}p$$

Combine -p and \frac{12}{5}p to get \frac{7}{5}p.

$$8+\frac{7}{5}p-4r$$

Factor

$$\frac{7p-20r+40}{5}$$

Solution Steps

Factor out \frac{1}{5}.

$$\frac{40+7p-20r}{5}$$

Consider 15-5p+25-20r+12p. Multiply and combine like terms.

$$7p-20r+40$$

Rewrite the complete factored expression.

$$\frac{7p-20r+40}{5}$$