Solve (3-2B^5)^2

$$( 3 - 2 B ^ { 5 } ) ^ { 2 }$$

Expand

$$4B^{10}-12B^{5}+9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-2B^{5}\right)^{2}.

$$9-12B^{5}+4\left(B^{5}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 5 and 2 to get 10.

$$9-12B^{5}+4B^{10}$$

Evaluate

$$\left(3-2B^{5}\right)^{2}$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-2B^{5}\right)^{2}.

$$9-12B^{5}+4\left(B^{5}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 5 and 2 to get 10.

$$9-12B^{5}+4B^{10}$$