Solve (3-12-5-4)-[-1+(-8+3-2)-(-1-6)]

$$( 3 - 12 - 5 - 4 ) - [ - 1 + ( - 8 + 3 - 2 ) - ( - 1 - 6 ) ]$$

Evaluate

$$-17$$

Solution Steps

Subtract 12 from 3 to get -9.

$$-9-5-4-\left(-1-8+3-2-\left(-1-6\right)\right)$$

Subtract 5 from -9 to get -14.

$$-14-4-\left(-1-8+3-2-\left(-1-6\right)\right)$$

Subtract 4 from -14 to get -18.

$$-18-\left(-1-8+3-2-\left(-1-6\right)\right)$$

Subtract 8 from -1 to get -9.

$$-18-\left(-9+3-2-\left(-1-6\right)\right)$$

Add -9 and 3 to get -6.

$$-18-\left(-6-2-\left(-1-6\right)\right)$$

Subtract 2 from -6 to get -8.

$$-18-\left(-8-\left(-1-6\right)\right)$$

Subtract 6 from -1 to get -7.

$$-18-\left(-8-\left(-7\right)\right)$$

The opposite of -7 is 7.

$$-18-\left(-8+7\right)$$

Add -8 and 7 to get -1.

$$-18-\left(-1\right)$$

The opposite of -1 is 1.

$$-18+1$$

Add -18 and 1 to get -17.

$$-17$$

Factor

$$-17$$