Solve (3)-3^2*(-1/3)^3

$$( 3 ) - 3 ^ { 2 } \times ( - \frac { 1 } { 3 } ) ^ { 3 }$$

Evaluate

$$\frac{10}{3}\approx 3.333333333$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$3-9\left(-\frac{1}{3}\right)^{3}$$

Calculate -\frac{1}{3} to the power of 3 and get -\frac{1}{27}.

$$3-9\left(-\frac{1}{27}\right)$$

Express 9\left(-\frac{1}{27}\right) as a single fraction.

$$3-\frac{9\left(-1\right)}{27}$$

Multiply 9 and -1 to get -9.

$$3-\frac{-9}{27}$$

Reduce the fraction \frac{-9}{27} to lowest terms by extracting and canceling out 9.

$$3-\left(-\frac{1}{3}\right)$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$3+\frac{1}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}+\frac{1}{3}$$

Since \frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{9+1}{3}$$

Add 9 and 1 to get 10.

$$\frac{10}{3}$$

Factor

$$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$$