Solve (3*(-3a-1)-10a+19=7*(2-3a)+12

$$( 3 \cdot ( - 3 a - 1 ) - 10 a + 19 = 7 \cdot ( 2 - 3 a ) + 12$$

Solve for a

$$a=5$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by -3a-1.

$$-9a-3-10a+19=7\left(2-3a\right)+12$$

Combine -9a and -10a to get -19a.

$$-19a-3+19=7\left(2-3a\right)+12$$

Add -3 and 19 to get 16.

$$-19a+16=7\left(2-3a\right)+12$$

Use the distributive property to multiply 7 by 2-3a.

$$-19a+16=14-21a+12$$

Add 14 and 12 to get 26.

$$-19a+16=26-21a$$

Add 21a to both sides.

$$-19a+16+21a=26$$

Combine -19a and 21a to get 2a.

$$2a+16=26$$

Subtract 16 from both sides.

$$2a=26-16$$

Subtract 16 from 26 to get 10.

$$2a=10$$

Divide both sides by 2.

$$a=\frac{10}{2}$$

Divide 10 by 2 to get 5.

$$a=5$$