Solve (3^x+2-9)div8=9

$$( 3 ^ { x + 2 } - 9 ) \div 8 = 9$$

Solve for x

$$x=2$$

Steps Using Definition of Logarithm

Multiply both sides by 8.

$$3^{x+2}-9=9\times 8$$

Multiply 9 and 8 to get 72.

$$3^{x+2}-9=72$$

Add 9 to both sides of the equation.

$$3^{x+2}=81$$

Take the logarithm of both sides of the equation.

$$\log(3^{x+2})=\log(81)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$\left(x+2\right)\log(3)=\log(81)$$

Divide both sides by \log(3).

$$x+2=\frac{\log(81)}{\log(3)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+2=\log_{3}\left(81\right)$$

Subtract 2 from both sides of the equation.

$$x=4-2$$

Solve for x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(3)}+2$$

$$n_{1}\in \mathrm{Z}$$