Solve (3^2+i^-1)*2^2

$$( 3 ^ { 2 } + i ^ { - 1 } ) \times 2 ^ { 2 }$$

Evaluate

$$36-4i$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\left(9+i^{-1}\right)\times 2^{2}$$

Calculate i to the power of -1 and get -i.

$$\left(9-i\right)\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\left(9-i\right)\times 4$$

Multiply 9-i and 4 to get 36-4i.

$$36-4i$$

Real Part

$$36$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$Re(\left(9+i^{-1}\right)\times 2^{2})$$

Calculate i to the power of -1 and get -i.

$$Re(\left(9-i\right)\times 2^{2})$$

Calculate 2 to the power of 2 and get 4.

$$Re(\left(9-i\right)\times 4)$$

Multiply 9-i and 4 to get 36-4i.

$$Re(36-4i)$$

The real part of 36-4i is 36.

$$36$$