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\left(\sqrt{3}+3\right)x=6
The equation is in standard form.
\frac{\left(\sqrt{3}+3\right)x}{\sqrt{3}+3}=\frac{6}{\sqrt{3}+3}
Divide both sides by 3+\sqrt{3}.
x=\frac{6}{\sqrt{3}+3}
Dividing by 3+\sqrt{3} undoes the multiplication by 3+\sqrt{3}.
x=3-\sqrt{3}
Divide 6 by 3+\sqrt{3}.