Solve (284+16)*(512-8208div18)quad120-36*4div18+3

$$( 284 + 16 ) \times ( 512 - 8208 \div 18 ) \quad 120 - 36 \times 4 \div 18 + 3$$

Evaluate

$$2015995$$

Solution Steps

Add 284 and 16 to get 300.

$$300\left(512-\frac{8208}{18}\right)\times 120-\frac{36\times 4}{18}+3$$

Divide 8208 by 18 to get 456.

$$300\left(512-456\right)\times 120-\frac{36\times 4}{18}+3$$

Subtract 456 from 512 to get 56.

$$300\times 56\times 120-\frac{36\times 4}{18}+3$$

Multiply 300 and 56 to get 16800.

$$16800\times 120-\frac{36\times 4}{18}+3$$

Multiply 16800 and 120 to get 2016000.

$$2016000-\frac{36\times 4}{18}+3$$

Multiply 36 and 4 to get 144.

$$2016000-\frac{144}{18}+3$$

Divide 144 by 18 to get 8.

$$2016000-8+3$$

Subtract 8 from 2016000 to get 2015992.

$$2015992+3$$

Add 2015992 and 3 to get 2015995.

$$2015995$$

Factor

$$5\times 19\times 21221$$