Solve (25-4)+3-(12-5*2)+(5+16div4)-5+(10-2^3)

$$( 25 - 4 ) + 3 - ( 12 - 5 * 2 ) + ( 5 + 16 \div 4 ) - 5 + ( 10 - 2 ^ { 3 } )$$

Evaluate

$$28$$

Solution Steps

Subtract 4 from 25 to get 21.

$$21+3-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Add 21 and 3 to get 24.

$$24-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Multiply 5 and 2 to get 10.

$$24-\left(12-10\right)+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 10 from 12 to get 2.

$$24-2+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 2 from 24 to get 22.

$$22+5+\frac{16}{4}-5+10-2^{3}$$

Add 22 and 5 to get 27.

$$27+\frac{16}{4}-5+10-2^{3}$$

Divide 16 by 4 to get 4.

$$27+4-5+10-2^{3}$$

Add 27 and 4 to get 31.

$$31-5+10-2^{3}$$

Subtract 5 from 31 to get 26.

$$26+10-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$26+10-8$$

Subtract 8 from 10 to get 2.

$$26+2$$

Add 26 and 2 to get 28.

$$28$$

Factor

$$2^{2}\times 7$$