Solve (255/6*18/25)-284/5

$$( 25 \frac { 5 } { 6 } \times \frac { 18 } { 25 } ) - 28 \frac { 4 } { 5 }$$

Evaluate

$$-\frac{51}{5}=-10.2$$

Solution Steps

Multiply 25 and 6 to get 150.

$$\frac{150+5}{6}\times \frac{18}{25}-\frac{28\times 5+4}{5}$$

Add 150 and 5 to get 155.

$$\frac{155}{6}\times \frac{18}{25}-\frac{28\times 5+4}{5}$$

Multiply \frac{155}{6} times \frac{18}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{155\times 18}{6\times 25}-\frac{28\times 5+4}{5}$$

Do the multiplications in the fraction \frac{155\times 18}{6\times 25}.

$$\frac{2790}{150}-\frac{28\times 5+4}{5}$$

Reduce the fraction \frac{2790}{150} to lowest terms by extracting and canceling out 30.

$$\frac{93}{5}-\frac{28\times 5+4}{5}$$

Multiply 28 and 5 to get 140.

$$\frac{93}{5}-\frac{140+4}{5}$$

Add 140 and 4 to get 144.

$$\frac{93}{5}-\frac{144}{5}$$

Since \frac{93}{5} and \frac{144}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{93-144}{5}$$

Subtract 144 from 93 to get -51.

$$-\frac{51}{5}$$

Factor

$$-\frac{51}{5} = -10\frac{1}{5} = -10.2$$