Solve (22-6*[[-32div8+(9-27)]-14]^3-(-2)

$$( 22 - 6 \cdot [ [ - 32 \div 8 + ( 9 - 27 ) ] - 14 ] ^ { 3 } - ( - 2 )$$

Evaluate

$$279960$$

Solution Steps

Divide -32 by 8 to get -4.

$$22-6\left(-4+9-27-14\right)^{3}-\left(-2\right)$$

Add -4 and 9 to get 5.

$$22-6\left(5-27-14\right)^{3}-\left(-2\right)$$

Subtract 27 from 5 to get -22.

$$22-6\left(-22-14\right)^{3}-\left(-2\right)$$

Subtract 14 from -22 to get -36.

$$22-6\left(-36\right)^{3}-\left(-2\right)$$

Calculate -36 to the power of 3 and get -46656.

$$22-6\left(-46656\right)-\left(-2\right)$$

Multiply 6 and -46656 to get -279936.

$$22-\left(-279936\right)-\left(-2\right)$$

The opposite of -279936 is 279936.

$$22+279936-\left(-2\right)$$

Add 22 and 279936 to get 279958.

$$279958-\left(-2\right)$$

The opposite of -2 is 2.

$$279958+2$$

Add 279958 and 2 to get 279960.

$$279960$$

Factor

$$2^{3}\times 3\times 5\times 2333$$