Solve (2x-3)(4x-2)-x(2x-3)=0

$$( 2 x - 3 ) ( 4 x - 2 ) - x ( 2 x - 3 ) = 0$$

Solve for x

$$x=\frac{2}{3}\approx 0.666666667$$

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps Using Factoring By Grouping

Use the distributive property to multiply 2x-3 by 4x-2 and combine like terms.

$$8x^{2}-16x+6-x\left(2x-3\right)=0$$

Use the distributive property to multiply x by 2x-3.

$$8x^{2}-16x+6-\left(2x^{2}-3x\right)=0$$

To find the opposite of 2x^{2}-3x, find the opposite of each term.

$$8x^{2}-16x+6-2x^{2}+3x=0$$

Combine 8x^{2} and -2x^{2} to get 6x^{2}.

$$6x^{2}-16x+6+3x=0$$

Combine -16x and 3x to get -13x.

$$6x^{2}-13x+6=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 6x^{2}+ax+bx+6. To find a and b, set up a system to be solved.

$$a+b=-13 ab=6\times 6=36$$

Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 36.

$$-1,-36 -2,-18 -3,-12 -4,-9 -6,-6$$

Calculate the sum for each pair.

$$-1-36=-37 -2-18=-20 -3-12=-15 -4-9=-13 -6-6=-12$$

The solution is the pair that gives sum -13.

$$a=-9 b=-4$$

Rewrite 6x^{2}-13x+6 as \left(6x^{2}-9x\right)+\left(-4x+6\right).

$$\left(6x^{2}-9x\right)+\left(-4x+6\right)$$

Factor out 3x in the first and -2 in the second group.

$$3x\left(2x-3\right)-2\left(2x-3\right)$$

Factor out common term 2x-3 by using distributive property.

$$\left(2x-3\right)\left(3x-2\right)$$

To find equation solutions, solve 2x-3=0 and 3x-2=0.

$$x=\frac{3}{2} x=\frac{2}{3}$$

Steps Using the Quadratic Formula

Use the distributive property to multiply 2x-3 by 4x-2 and combine like terms.

$$8x^{2}-16x+6-x\left(2x-3\right)=0$$

Use the distributive property to multiply x by 2x-3.

$$8x^{2}-16x+6-\left(2x^{2}-3x\right)=0$$

To find the opposite of 2x^{2}-3x, find the opposite of each term.

$$8x^{2}-16x+6-2x^{2}+3x=0$$

Combine 8x^{2} and -2x^{2} to get 6x^{2}.

$$6x^{2}-16x+6+3x=0$$

Combine -16x and 3x to get -13x.

$$6x^{2}-13x+6=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, -13 for b, and 6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 6\times 6}}{2\times 6}$$

Square -13.

$$x=\frac{-\left(-13\right)±\sqrt{169-4\times 6\times 6}}{2\times 6}$$

Multiply -4 times 6.

$$x=\frac{-\left(-13\right)±\sqrt{169-24\times 6}}{2\times 6}$$

Multiply -24 times 6.

$$x=\frac{-\left(-13\right)±\sqrt{169-144}}{2\times 6}$$

Add 169 to -144.

$$x=\frac{-\left(-13\right)±\sqrt{25}}{2\times 6}$$

Take the square root of 25.

$$x=\frac{-\left(-13\right)±5}{2\times 6}$$

The opposite of -13 is 13.

$$x=\frac{13±5}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{13±5}{12}$$

Now solve the equation x=\frac{13±5}{12} when ± is plus. Add 13 to 5.

$$x=\frac{18}{12}$$

Reduce the fraction \frac{18}{12} to lowest terms by extracting and canceling out 6.

$$x=\frac{3}{2}$$

Now solve the equation x=\frac{13±5}{12} when ± is minus. Subtract 5 from 13.

$$x=\frac{8}{12}$$

Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.

$$x=\frac{2}{3}$$

The equation is now solved.

$$x=\frac{3}{2} x=\frac{2}{3}$$

Steps for Completing the Square

Use the distributive property to multiply 2x-3 by 4x-2 and combine like terms.

$$8x^{2}-16x+6-x\left(2x-3\right)=0$$

Use the distributive property to multiply x by 2x-3.

$$8x^{2}-16x+6-\left(2x^{2}-3x\right)=0$$

To find the opposite of 2x^{2}-3x, find the opposite of each term.

$$8x^{2}-16x+6-2x^{2}+3x=0$$

Combine 8x^{2} and -2x^{2} to get 6x^{2}.

$$6x^{2}-16x+6+3x=0$$

Combine -16x and 3x to get -13x.

$$6x^{2}-13x+6=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$6x^{2}-13x=-6$$

Divide both sides by 6.

$$\frac{6x^{2}-13x}{6}=-\frac{6}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x^{2}-\frac{13}{6}x=-\frac{6}{6}$$

Divide -6 by 6.

$$x^{2}-\frac{13}{6}x=-1$$

Divide -\frac{13}{6}, the coefficient of the x term, by 2 to get -\frac{13}{12}. Then add the square of -\frac{13}{12} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-\frac{13}{6}x+\left(-\frac{13}{12}\right)^{2}=-1+\left(-\frac{13}{12}\right)^{2}$$

Square -\frac{13}{12} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-\frac{13}{6}x+\frac{169}{144}=-1+\frac{169}{144}$$

Add -1 to \frac{169}{144}.

$$x^{2}-\frac{13}{6}x+\frac{169}{144}=\frac{25}{144}$$

Factor x^{2}-\frac{13}{6}x+\frac{169}{144}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{13}{12}\right)^{2}=\frac{25}{144}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{13}{12}\right)^{2}}=\sqrt{\frac{25}{144}}$$

Simplify.

$$x-\frac{13}{12}=\frac{5}{12} x-\frac{13}{12}=-\frac{5}{12}$$

Add \frac{13}{12} to both sides of the equation.

$$x=\frac{3}{2} x=\frac{2}{3}$$