Solve (2x^2y^3)^3=

$$( 2 x ^ { 2 } y ^ { 3 } ) ^ { 3 } =$$

Evaluate

$$8x^{6}y^{9}$$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\left(2x^{2}y^{3}\right)^{3}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$2^{3}\left(x^{2}\right)^{3}\left(y^{3}\right)^{3}$$

Raise 2 to the power 3.

$$8\left(x^{2}\right)^{3}\left(y^{3}\right)^{3}$$

To raise a power to another power, multiply the exponents.

$$8x^{2\times 3}y^{3\times 3}$$

Multiply 2 times 3.

$$8x^{6}y^{3\times 3}$$

Multiply 3 times 3.

$$8x^{6}y^{9}$$

Expand

$$8x^{6}y^{9}$$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\left(2x^{2}y^{3}\right)^{3}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$2^{3}\left(x^{2}\right)^{3}\left(y^{3}\right)^{3}$$

Raise 2 to the power 3.

$$8\left(x^{2}\right)^{3}\left(y^{3}\right)^{3}$$

To raise a power to another power, multiply the exponents.

$$8x^{2\times 3}y^{3\times 3}$$

Multiply 2 times 3.

$$8x^{6}y^{3\times 3}$$

Multiply 3 times 3.

$$8x^{6}y^{9}$$