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4x^{2}+4xy+y^{2}-\left(2x+y\right)\left(2x-y\right)-\frac{1}{2}xy
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+y\right)^{2}.
4x^{2}+4xy+y^{2}-\left(\left(2x\right)^{2}-y^{2}\right)-\frac{1}{2}xy
Consider \left(2x+y\right)\left(2x-y\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
4x^{2}+4xy+y^{2}-\left(2^{2}x^{2}-y^{2}\right)-\frac{1}{2}xy
Expand \left(2x\right)^{2}.
4x^{2}+4xy+y^{2}-\left(4x^{2}-y^{2}\right)-\frac{1}{2}xy
Calculate 2 to the power of 2 and get 4.
4x^{2}+4xy+y^{2}-4x^{2}+y^{2}-\frac{1}{2}xy
To find the opposite of 4x^{2}-y^{2}, find the opposite of each term.
4xy+y^{2}+y^{2}-\frac{1}{2}xy
Combine 4x^{2} and -4x^{2} to get 0.
4xy+2y^{2}-\frac{1}{2}xy
Combine y^{2} and y^{2} to get 2y^{2}.
\frac{7}{2}xy+2y^{2}
Combine 4xy and -\frac{1}{2}xy to get \frac{7}{2}xy.
4x^{2}+4xy+y^{2}-\left(2x+y\right)\left(2x-y\right)-\frac{1}{2}xy
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+y\right)^{2}.
4x^{2}+4xy+y^{2}-\left(\left(2x\right)^{2}-y^{2}\right)-\frac{1}{2}xy
Consider \left(2x+y\right)\left(2x-y\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
4x^{2}+4xy+y^{2}-\left(2^{2}x^{2}-y^{2}\right)-\frac{1}{2}xy
Expand \left(2x\right)^{2}.
4x^{2}+4xy+y^{2}-\left(4x^{2}-y^{2}\right)-\frac{1}{2}xy
Calculate 2 to the power of 2 and get 4.
4x^{2}+4xy+y^{2}-4x^{2}+y^{2}-\frac{1}{2}xy
To find the opposite of 4x^{2}-y^{2}, find the opposite of each term.
4xy+y^{2}+y^{2}-\frac{1}{2}xy
Combine 4x^{2} and -4x^{2} to get 0.
4xy+2y^{2}-\frac{1}{2}xy
Combine y^{2} and y^{2} to get 2y^{2}.
\frac{7}{2}xy+2y^{2}
Combine 4xy and -\frac{1}{2}xy to get \frac{7}{2}xy.