Solve for x
x=\frac{\sqrt{5}-3}{2}\approx -0.381966011
x=\frac{-\sqrt{5}-3}{2}\approx -2.618033989
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2x+3=\sqrt{5} 2x+3=-\sqrt{5}
Take the square root of both sides of the equation.
2x+3-3=\sqrt{5}-3 2x+3-3=-\sqrt{5}-3
Subtract 3 from both sides of the equation.
2x=\sqrt{5}-3 2x=-\sqrt{5}-3
Subtracting 3 from itself leaves 0.
2x=\sqrt{5}-3
Subtract 3 from \sqrt{5}.
2x=-\sqrt{5}-3
Subtract 3 from -\sqrt{5}.
\frac{2x}{2}=\frac{\sqrt{5}-3}{2} \frac{2x}{2}=\frac{-\sqrt{5}-3}{2}
Divide both sides by 2.
x=\frac{\sqrt{5}-3}{2} x=\frac{-\sqrt{5}-3}{2}
Dividing by 2 undoes the multiplication by 2.
Examples
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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