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Solve for x (complex solution)
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4x^{2}+12x+9=4x^{2}+12x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+3\right)^{2}.
4x^{2}+12x+9-4x^{2}=12x+9
Subtract 4x^{2} from both sides.
12x+9=12x+9
Combine 4x^{2} and -4x^{2} to get 0.
12x+9-12x=9
Subtract 12x from both sides.
9=9
Combine 12x and -12x to get 0.
\text{true}
Compare 9 and 9.
x\in \mathrm{C}
This is true for any x.
4x^{2}+12x+9=4x^{2}+12x+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+3\right)^{2}.
4x^{2}+12x+9-4x^{2}=12x+9
Subtract 4x^{2} from both sides.
12x+9=12x+9
Combine 4x^{2} and -4x^{2} to get 0.
12x+9-12x=9
Subtract 12x from both sides.
9=9
Combine 12x and -12x to get 0.
\text{true}
Compare 9 and 9.
x\in \mathrm{R}
This is true for any x.