Solve (2x+1)*y=42

$$( 2 x + 1 ) \cdot y = 42$$

Solve for x

$$x=-\frac{1}{2}+\frac{21}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2x+1 by y.

$$2xy+y=42$$

Subtract y from both sides.

$$2xy=42-y$$

The equation is in standard form.

$$2yx=42-y$$

Divide both sides by 2y.

$$\frac{2yx}{2y}=\frac{42-y}{2y}$$

Dividing by 2y undoes the multiplication by 2y.

$$x=\frac{42-y}{2y}$$

Divide 42-y by 2y.

$$x=-\frac{1}{2}+\frac{21}{y}$$

Solve for y

$$y=\frac{42}{2x+1}$$

$$x\neq -\frac{1}{2}$$

Steps for Solving Linear Equation

Divide both sides by 2x+1.

$$\frac{\left(2x+1\right)y}{2x+1}=\frac{42}{2x+1}$$

Dividing by 2x+1 undoes the multiplication by 2x+1.

$$y=\frac{42}{2x+1}$$