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2x+\frac{3}{4}=\frac{7}{5} 2x+\frac{3}{4}=-\frac{7}{5}
Take the square root of both sides of the equation.
2x+\frac{3}{4}-\frac{3}{4}=\frac{7}{5}-\frac{3}{4} 2x+\frac{3}{4}-\frac{3}{4}=-\frac{7}{5}-\frac{3}{4}
Subtract \frac{3}{4} from both sides of the equation.
2x=\frac{7}{5}-\frac{3}{4} 2x=-\frac{7}{5}-\frac{3}{4}
Subtracting \frac{3}{4} from itself leaves 0.
2x=\frac{13}{20}
Subtract \frac{3}{4} from \frac{7}{5} by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
2x=-\frac{43}{20}
Subtract \frac{3}{4} from -\frac{7}{5} by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
\frac{2x}{2}=\frac{\frac{13}{20}}{2} \frac{2x}{2}=-\frac{\frac{43}{20}}{2}
Divide both sides by 2.
x=\frac{\frac{13}{20}}{2} x=-\frac{\frac{43}{20}}{2}
Dividing by 2 undoes the multiplication by 2.
x=\frac{13}{40}
Divide \frac{13}{20} by 2.
x=-\frac{43}{40}
Divide -\frac{43}{20} by 2.
x=\frac{13}{40} x=-\frac{43}{40}
The equation is now solved.