Solve (2k+1)^2=60

$$( 2 k + 1 ) ^ { 2 } = 60$$

Solve for k

$$k=\sqrt{15}-\frac{1}{2}\approx 3.372983346$$

$$k=-\sqrt{15}-\frac{1}{2}\approx -4.372983346$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$2k+1=2\sqrt{15} 2k+1=-2\sqrt{15}$$

Subtract 1 from both sides of the equation.

$$2k+1-1=2\sqrt{15}-1 2k+1-1=-2\sqrt{15}-1$$

Subtracting 1 from itself leaves 0.

$$2k=2\sqrt{15}-1 2k=-2\sqrt{15}-1$$

Subtract 1 from 2\sqrt{15}.

$$2k=2\sqrt{15}-1$$

Subtract 1 from -2\sqrt{15}.

$$2k=-2\sqrt{15}-1$$

Divide both sides by 2.

$$\frac{2k}{2}=\frac{2\sqrt{15}-1}{2} \frac{2k}{2}=\frac{-2\sqrt{15}-1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$k=\frac{2\sqrt{15}-1}{2} k=\frac{-2\sqrt{15}-1}{2}$$

Divide 2\sqrt{15}-1 by 2.

$$k=\sqrt{15}-\frac{1}{2}$$

Divide -2\sqrt{15}-1 by 2.

$$k=-\sqrt{15}-\frac{1}{2}$$

The equation is now solved.

$$k=\sqrt{15}-\frac{1}{2} k=-\sqrt{15}-\frac{1}{2}$$