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Real Part
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2i\times 4+2\left(-3\right)i^{2}
Multiply 2i times 4-3i.
2i\times 4+2\left(-3\right)\left(-1\right)
By definition, i^{2} is -1.
6+8i
Do the multiplications. Reorder the terms.
Re(2i\times 4+2\left(-3\right)i^{2})
Multiply 2i times 4-3i.
Re(2i\times 4+2\left(-3\right)\left(-1\right))
By definition, i^{2} is -1.
Re(6+8i)
Do the multiplications in 2i\times 4+2\left(-3\right)\left(-1\right). Reorder the terms.
6
The real part of 6+8i is 6.