Solve (2ab)(-3ab)(-4a)=

$$( 2 a b ) ( - 3 a b ) ( - 4 a ) =$$

Evaluate

$$24b^{2}a^{3}$$

Solution Steps

Multiply a and a to get a^{2}.

$$2a^{2}b\left(-3\right)b\left(-4\right)a$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$2a^{3}b\left(-3\right)b\left(-4\right)$$

Multiply b and b to get b^{2}.

$$2a^{3}b^{2}\left(-3\right)\left(-4\right)$$

Multiply 2 and -3 to get -6.

$$-6a^{3}b^{2}\left(-4\right)$$

Multiply -6 and -4 to get 24.

$$24a^{3}b^{2}$$

Differentiate w.r.t. b

$$48ba^{3}$$