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8a^{3}-12a^{2}+6a-1-27+a^{3}
Use binomial theorem \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} to expand \left(2a-1\right)^{3}.
8a^{3}-12a^{2}+6a-28+a^{3}
Subtract 27 from -1 to get -28.
9a^{3}-12a^{2}+6a-28
Combine 8a^{3} and a^{3} to get 9a^{3}.
8a^{3}-12a^{2}+6a-1-27+a^{3}
Use binomial theorem \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} to expand \left(2a-1\right)^{3}.
8a^{3}-12a^{2}+6a-28+a^{3}
Subtract 27 from -1 to get -28.
9a^{3}-12a^{2}+6a-28
Combine 8a^{3} and a^{3} to get 9a^{3}.