Solve (2a)*(-3ab)*(-3ab^2)=

$$( 2 a ) \cdot ( - 3 a b ) \cdot ( - 3 a b ^ { 2 } ) =$$

Evaluate

$$18\left(ab\right)^{3}$$

Solution Steps

Multiply a and a to get a^{2}.

$$2a^{2}\left(-3\right)b\left(-3\right)ab^{2}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$2a^{3}\left(-3\right)b\left(-3\right)b^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2a^{3}\left(-3\right)b^{3}\left(-3\right)$$

Multiply 2 and -3 to get -6.

$$-6a^{3}b^{3}\left(-3\right)$$

Multiply -6 and -3 to get 18.

$$18a^{3}b^{3}$$

Differentiate w.r.t. b

$$54b^{2}a^{3}$$