Solve (2-4i)-(5+3i)-(-6+i)

$$( 2 - 4 i ) - ( 5 + 3 i ) - ( - 6 + i )$$

Evaluate

$$3-8i$$

Solution Steps

Subtract 5+3i from 2-4i by subtracting corresponding real and imaginary parts.

$$2-5+\left(-4-3\right)i-\left(-6+i\right)$$

Subtract 5 from 2. Subtract 3 from -4.

$$-3-7i-\left(-6+i\right)$$

Subtract -6+i from -3-7i by subtracting corresponding real and imaginary parts.

$$-3-\left(-6\right)+\left(-7-1\right)i$$

Subtract -6 from -3. Subtract 1 from -7.

$$3-8i$$

Real Part

$$3$$

Solution Steps

Subtract 5+3i from 2-4i by subtracting corresponding real and imaginary parts.

$$Re(2-5+\left(-4-3\right)i-\left(-6+i\right))$$

Subtract 5 from 2. Subtract 3 from -4.

$$Re(-3-7i-\left(-6+i\right))$$

Subtract -6+i from -3-7i by subtracting corresponding real and imaginary parts.

$$Re(-3-\left(-6\right)+\left(-7-1\right)i)$$

Subtract -6 from -3. Subtract 1 from -7.

$$Re(3-8i)$$

The real part of 3-8i is 3.

$$3$$