Solve (2*7/3+5)*(5*7/3-2)

$$( 2 \times \frac { 7 } { 3 } + 5 ) \times ( 5 \times \frac { 7 } { 3 } - 2 )$$

Evaluate

$$\frac{841}{9}\approx 93.444444444$$

Solution Steps

Express 2\times \frac{7}{3} as a single fraction.

$$\left(\frac{2\times 7}{3}+5\right)\left(5\times \frac{7}{3}-2\right)$$

Multiply 2 and 7 to get 14.

$$\left(\frac{14}{3}+5\right)\left(5\times \frac{7}{3}-2\right)$$

Convert 5 to fraction \frac{15}{3}.

$$\left(\frac{14}{3}+\frac{15}{3}\right)\left(5\times \frac{7}{3}-2\right)$$

Since \frac{14}{3} and \frac{15}{3} have the same denominator, add them by adding their numerators.

$$\frac{14+15}{3}\left(5\times \frac{7}{3}-2\right)$$

Add 14 and 15 to get 29.

$$\frac{29}{3}\left(5\times \frac{7}{3}-2\right)$$

Express 5\times \frac{7}{3} as a single fraction.

$$\frac{29}{3}\left(\frac{5\times 7}{3}-2\right)$$

Multiply 5 and 7 to get 35.

$$\frac{29}{3}\left(\frac{35}{3}-2\right)$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{29}{3}\left(\frac{35}{3}-\frac{6}{3}\right)$$

Since \frac{35}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29}{3}\times \frac{35-6}{3}$$

Subtract 6 from 35 to get 29.

$$\frac{29}{3}\times \frac{29}{3}$$

Multiply \frac{29}{3} times \frac{29}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{29\times 29}{3\times 3}$$

Do the multiplications in the fraction \frac{29\times 29}{3\times 3}.

$$\frac{841}{9}$$

Factor

$$\frac{29 ^ {2}}{3 ^ {2}} = 93\frac{4}{9} = 93.44444444444444$$