Solve (2sqrt{6})^2+(2sqrt{6})^2

$$( 2 \sqrt { 6 } ) ^ { 2 } + ( 2 \sqrt { 6 } ) ^ { 2 }$$

Evaluate

$$48$$

Solution Steps

Expand \left(2\sqrt{6}\right)^{2}.

$$2^{2}\left(\sqrt{6}\right)^{2}+\left(2\sqrt{6}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$4\left(\sqrt{6}\right)^{2}+\left(2\sqrt{6}\right)^{2}$$

The square of \sqrt{6} is 6.

$$4\times 6+\left(2\sqrt{6}\right)^{2}$$

Multiply 4 and 6 to get 24.

$$24+\left(2\sqrt{6}\right)^{2}$$

Expand \left(2\sqrt{6}\right)^{2}.

$$24+2^{2}\left(\sqrt{6}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$24+4\left(\sqrt{6}\right)^{2}$$

The square of \sqrt{6} is 6.

$$24+4\times 6$$

Multiply 4 and 6 to get 24.

$$24+24$$

Add 24 and 24 to get 48.

$$48$$

Factor

$$2^{4}\times 3$$