Evaluate
37-20\sqrt{3}\approx 2.358983849
Expand
37-20\sqrt{3}
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4\left(\sqrt{3}\right)^{2}-20\sqrt{3}+25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2\sqrt{3}-5\right)^{2}.
4\times 3-20\sqrt{3}+25
The square of \sqrt{3} is 3.
12-20\sqrt{3}+25
Multiply 4 and 3 to get 12.
37-20\sqrt{3}
Add 12 and 25 to get 37.
4\left(\sqrt{3}\right)^{2}-20\sqrt{3}+25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2\sqrt{3}-5\right)^{2}.
4\times 3-20\sqrt{3}+25
The square of \sqrt{3} is 3.
12-20\sqrt{3}+25
Multiply 4 and 3 to get 12.
37-20\sqrt{3}
Add 12 and 25 to get 37.
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