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\left(2\sqrt{3}\right)^{2}-\left(\sqrt{7}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
2^{2}\left(\sqrt{3}\right)^{2}-\left(\sqrt{7}\right)^{2}
Expand \left(2\sqrt{3}\right)^{2}.
4\left(\sqrt{3}\right)^{2}-\left(\sqrt{7}\right)^{2}
Calculate 2 to the power of 2 and get 4.
4\times 3-\left(\sqrt{7}\right)^{2}
The square of \sqrt{3} is 3.
12-\left(\sqrt{7}\right)^{2}
Multiply 4 and 3 to get 12.
12-7
The square of \sqrt{7} is 7.
5
Subtract 7 from 12 to get 5.