Solve (25/18-51/12+12/9)*(0,81:0,4)

$$( 2 \frac { 5 } { 18 } - 5 \frac { 1 } { 12 } + 1 \frac { 2 } { 9 } ) \cdot ( 0,81 : 0,4 )$$

Evaluate

$$-3,20625$$

Solution Steps

Multiply 2 and 18 to get 36.

$$\left(\frac{36+5}{18}-\frac{5\times 12+1}{12}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Add 36 and 5 to get 41.

$$\left(\frac{41}{18}-\frac{5\times 12+1}{12}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Multiply 5 and 12 to get 60.

$$\left(\frac{41}{18}-\frac{60+1}{12}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Add 60 and 1 to get 61.

$$\left(\frac{41}{18}-\frac{61}{12}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Least common multiple of 18 and 12 is 36. Convert \frac{41}{18} and \frac{61}{12} to fractions with denominator 36.

$$\left(\frac{82}{36}-\frac{183}{36}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Since \frac{82}{36} and \frac{183}{36} have the same denominator, subtract them by subtracting their numerators.

$$\left(\frac{82-183}{36}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Subtract 183 from 82 to get -101.

$$\left(-\frac{101}{36}+\frac{1\times 9+2}{9}\right)\times \frac{0,81}{0,4}$$

Multiply 1 and 9 to get 9.

$$\left(-\frac{101}{36}+\frac{9+2}{9}\right)\times \frac{0,81}{0,4}$$

Add 9 and 2 to get 11.

$$\left(-\frac{101}{36}+\frac{11}{9}\right)\times \frac{0,81}{0,4}$$

Least common multiple of 36 and 9 is 36. Convert -\frac{101}{36} and \frac{11}{9} to fractions with denominator 36.

$$\left(-\frac{101}{36}+\frac{44}{36}\right)\times \frac{0,81}{0,4}$$

Since -\frac{101}{36} and \frac{44}{36} have the same denominator, add them by adding their numerators.

$$\frac{-101+44}{36}\times \frac{0,81}{0,4}$$

Add -101 and 44 to get -57.

$$\frac{-57}{36}\times \frac{0,81}{0,4}$$

Reduce the fraction \frac{-57}{36} to lowest terms by extracting and canceling out 3.

$$-\frac{19}{12}\times \frac{0,81}{0,4}$$

Expand \frac{0,81}{0,4} by multiplying both numerator and the denominator by 100.

$$-\frac{19}{12}\times \frac{81}{40}$$

Multiply -\frac{19}{12} times \frac{81}{40} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-19\times 81}{12\times 40}$$

Do the multiplications in the fraction \frac{-19\times 81}{12\times 40}.

$$\frac{-1539}{480}$$

Reduce the fraction \frac{-1539}{480} to lowest terms by extracting and canceling out 3.

$$-\frac{513}{160}$$

Factor

$$-3,20625$$