Solve (2^3)^6*(2^2)^2

$$( 2 ^ { 3 } ) ^ { 6 } \times ( 2 ^ { 2 } ) ^ { 2 }$$

Evaluate

$$4194304$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 6 to get 18.

$$2^{18}\times \left(2^{2}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$2^{18}\times 2^{4}$$

To multiply powers of the same base, add their exponents. Add 18 and 4 to get 22.

$$2^{22}$$

Calculate 2 to the power of 22 and get 4194304.

$$4194304$$

Factor

$$2^{22}$$