Solve (2^3)^2-(9-5)^3*4^-5

$$( 2 ^ { 3 } ) ^ { 2 } - ( 9 - 5 ) ^ { 3 } \cdot 4 ^ { - 5 }$$

Evaluate

$$\frac{1023}{16}=63.9375$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$2^{6}-\left(9-5\right)^{3}\times 4^{-5}$$

Calculate 2 to the power of 6 and get 64.

$$64-\left(9-5\right)^{3}\times 4^{-5}$$

Subtract 5 from 9 to get 4.

$$64-4^{3}\times 4^{-5}$$

Calculate 4 to the power of 3 and get 64.

$$64-64\times 4^{-5}$$

Calculate 4 to the power of -5 and get \frac{1}{1024}.

$$64-64\times \frac{1}{1024}$$

Multiply 64 and \frac{1}{1024} to get \frac{1}{16}.

$$64-\frac{1}{16}$$

Subtract \frac{1}{16} from 64 to get \frac{1023}{16}.

$$\frac{1023}{16}$$

Factor

$$\frac{3 \cdot 11 \cdot 31}{2 ^ {4}} = 63\frac{15}{16} = 63.9375$$