Solve (2^-3)^2*(-3)^-3*(-6)^3

$$( 2 ^ { - 3 } ) ^ { 2 } \cdot ( - 3 ) ^ { - 3 } \cdot ( - 6 ) ^ { 3 }$$

Evaluate

$$\frac{1}{8}=0.125$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -3 and 2 to get -6.

$$2^{-6}\left(-3\right)^{-3}\left(-6\right)^{3}$$

Calculate 2 to the power of -6 and get \frac{1}{64}.

$$\frac{1}{64}\left(-3\right)^{-3}\left(-6\right)^{3}$$

Calculate -3 to the power of -3 and get -\frac{1}{27}.

$$\frac{1}{64}\left(-\frac{1}{27}\right)\left(-6\right)^{3}$$

Multiply \frac{1}{64} and -\frac{1}{27} to get -\frac{1}{1728}.

$$-\frac{1}{1728}\left(-6\right)^{3}$$

Calculate -6 to the power of 3 and get -216.

$$-\frac{1}{1728}\left(-216\right)$$

Multiply -\frac{1}{1728} and -216 to get \frac{1}{8}.

$$\frac{1}{8}$$

Factor

$$\frac{1}{2 ^ {3}} = 0.125$$