Solve (2+5)*4+3(1+9(2+3)+(4+2)*3)

$$( 2 + 5 ) \cdot 4 + 3 ( 1 + 9 ( 2 + 3 ) + ( 4 + 2 ) \cdot 3 )$$

Evaluate

$$220$$

Solution Steps

Add 2 and 5 to get 7.

$$7\times 4+3\left(1+9\left(2+3\right)+\left(4+2\right)\times 3\right)$$

Multiply 7 and 4 to get 28.

$$28+3\left(1+9\left(2+3\right)+\left(4+2\right)\times 3\right)$$

Add 2 and 3 to get 5.

$$28+3\left(1+9\times 5+\left(4+2\right)\times 3\right)$$

Multiply 9 and 5 to get 45.

$$28+3\left(1+45+\left(4+2\right)\times 3\right)$$

Add 1 and 45 to get 46.

$$28+3\left(46+\left(4+2\right)\times 3\right)$$

Add 4 and 2 to get 6.

$$28+3\left(46+6\times 3\right)$$

Multiply 6 and 3 to get 18.

$$28+3\left(46+18\right)$$

Add 46 and 18 to get 64.

$$28+3\times 64$$

Multiply 3 and 64 to get 192.

$$28+192$$

Add 28 and 192 to get 220.

$$220$$

Factor

$$2^{2}\times 5\times 11$$