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-1
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-1
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2\sqrt{3}-4+\left(\sqrt{3}\right)^{2}-2\sqrt{3}
Apply the distributive property by multiplying each term of 2+\sqrt{3} by each term of \sqrt{3}-2.
2\sqrt{3}-4+3-2\sqrt{3}
The square of \sqrt{3} is 3.
2\sqrt{3}-1-2\sqrt{3}
Add -4 and 3 to get -1.
-1
Combine 2\sqrt{3} and -2\sqrt{3} to get 0.
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