Evaluate
4\sqrt{3}+7\approx 13.92820323
Expand
4 \sqrt{3} + 7 = 13.92820323
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4+4\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2+\sqrt{3}\right)^{2}.
4+4\sqrt{3}+3
The square of \sqrt{3} is 3.
7+4\sqrt{3}
Add 4 and 3 to get 7.
4+4\sqrt{3}+\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2+\sqrt{3}\right)^{2}.
4+4\sqrt{3}+3
The square of \sqrt{3} is 3.
7+4\sqrt{3}
Add 4 and 3 to get 7.
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