Solve (17*2-3^{2}):5+(11*3+2)^2:5^2-2^2*3^2

$$( 17 \times 2 - 3 ^ { 2 } ) : 5 + ( 11 \times 3 + 2 ) ^ { 2 } : 5 ^ { 2 } - 2 ^ { 2 } \times 3 ^ { 2 }$$

Evaluate

$$18$$

Solution Steps

Multiply 17 and 2 to get 34.

$$\frac{34-3^{2}}{5}+\frac{\left(11\times 3+2\right)^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{34-9}{5}+\frac{\left(11\times 3+2\right)^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Subtract 9 from 34 to get 25.

$$\frac{25}{5}+\frac{\left(11\times 3+2\right)^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Divide 25 by 5 to get 5.

$$5+\frac{\left(11\times 3+2\right)^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Multiply 11 and 3 to get 33.

$$5+\frac{\left(33+2\right)^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Add 33 and 2 to get 35.

$$5+\frac{35^{2}}{5^{2}}-2^{2}\times 3^{2}$$

Calculate 35 to the power of 2 and get 1225.

$$5+\frac{1225}{5^{2}}-2^{2}\times 3^{2}$$

Calculate 5 to the power of 2 and get 25.

$$5+\frac{1225}{25}-2^{2}\times 3^{2}$$

Divide 1225 by 25 to get 49.

$$5+49-2^{2}\times 3^{2}$$

Add 5 and 49 to get 54.

$$54-2^{2}\times 3^{2}$$

Calculate 2 to the power of 2 and get 4.

$$54-4\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$54-4\times 9$$

Multiply 4 and 9 to get 36.

$$54-36$$

Subtract 36 from 54 to get 18.

$$18$$

Factor

$$2\times 3^{2}$$