Solve (13-6)+3N_{1}13

$$( 13 - 6 ) + 3 N _ { 1 } 13$$

Evaluate

$$39N_{1}+7$$

Solution Steps

Subtract 6 from 13 to get 7.

$$7+3N_{1}\times 13$$

Multiply 3 and 13 to get 39.

$$7+39N_{1}$$

Differentiate w.r.t. N_1

$$39$$

Steps Using Derivative Rule for Sum

Subtract 6 from 13 to get 7.

$$\frac{\mathrm{d}}{\mathrm{d}N_{1}}(7+3N_{1}\times 13)$$

Multiply 3 and 13 to get 39.

$$\frac{\mathrm{d}}{\mathrm{d}N_{1}}(7+39N_{1})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$39N_{1}^{1-1}$$

Subtract 1 from 1.

$$39N_{1}^{0}$$

For any term t except 0, t^{0}=1.

$$39\times 1$$

For any term t, t\times 1=t and 1t=t.

$$39$$