Solve for a
a=3
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12+a=3\left(3a-4\right)
Variable a cannot be equal to \frac{4}{3} since division by zero is not defined. Multiply both sides of the equation by 2\left(3a-4\right), the least common multiple of 6a-8,2.
12+a=9a-12
Use the distributive property to multiply 3 by 3a-4.
12+a-9a=-12
Subtract 9a from both sides.
12-8a=-12
Combine a and -9a to get -8a.
-8a=-12-12
Subtract 12 from both sides.
-8a=-24
Subtract 12 from -12 to get -24.
a=\frac{-24}{-8}
Divide both sides by -8.
a=3
Divide -24 by -8 to get 3.
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