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104^{2n}=2
Use the rules of exponents and logarithms to solve the equation.
\log(104^{2n})=\log(2)
Take the logarithm of both sides of the equation.
2n\log(104)=\log(2)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2n=\frac{\log(2)}{\log(104)}
Divide both sides by \log(104).
2n=\log_{104}\left(2\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
n=\frac{\log_{104}\left(2\right)}{2}
Divide both sides by 2.