Solve (100-x)*80=[100(1-41/3)-x](80+4*4)

$$( 100 - x ) \times 80 = [ 100 ( 1 - 41 / 3 ) - x ] ( 80 + 4 \times 4 )$$

Solve for x

$$x=-8100$$

Steps for Solving Linear Equation

Use the distributive property to multiply 100-x by 80.

$$8000-80x=\left(100\left(1-\frac{41}{3}\right)-x\right)\left(80+4\times 4\right)$$

Convert 1 to fraction \frac{3}{3}.

$$8000-80x=\left(100\left(\frac{3}{3}-\frac{41}{3}\right)-x\right)\left(80+4\times 4\right)$$

Since \frac{3}{3} and \frac{41}{3} have the same denominator, subtract them by subtracting their numerators.

$$8000-80x=\left(100\times \frac{3-41}{3}-x\right)\left(80+4\times 4\right)$$

Subtract 41 from 3 to get -38.

$$8000-80x=\left(100\left(-\frac{38}{3}\right)-x\right)\left(80+4\times 4\right)$$

Express 100\left(-\frac{38}{3}\right) as a single fraction.

$$8000-80x=\left(\frac{100\left(-38\right)}{3}-x\right)\left(80+4\times 4\right)$$

Multiply 100 and -38 to get -3800.

$$8000-80x=\left(\frac{-3800}{3}-x\right)\left(80+4\times 4\right)$$

Fraction \frac{-3800}{3} can be rewritten as -\frac{3800}{3} by extracting the negative sign.

$$8000-80x=\left(-\frac{3800}{3}-x\right)\left(80+4\times 4\right)$$

Multiply 4 and 4 to get 16.

$$8000-80x=\left(-\frac{3800}{3}-x\right)\left(80+16\right)$$

Add 80 and 16 to get 96.

$$8000-80x=\left(-\frac{3800}{3}-x\right)\times 96$$

Use the distributive property to multiply -\frac{3800}{3}-x by 96.

$$8000-80x=-\frac{3800}{3}\times 96-96x$$

Express -\frac{3800}{3}\times 96 as a single fraction.

$$8000-80x=\frac{-3800\times 96}{3}-96x$$

Multiply -3800 and 96 to get -364800.

$$8000-80x=\frac{-364800}{3}-96x$$

Divide -364800 by 3 to get -121600.

$$8000-80x=-121600-96x$$

Add 96x to both sides.

$$8000-80x+96x=-121600$$

Combine -80x and 96x to get 16x.

$$8000+16x=-121600$$

Subtract 8000 from both sides.

$$16x=-121600-8000$$

Subtract 8000 from -121600 to get -129600.

$$16x=-129600$$

Divide both sides by 16.

$$x=\frac{-129600}{16}$$

Divide -129600 by 16 to get -8100.

$$x=-8100$$