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\left(8-2\right)x\geq 6-1.2
Subtract 2 from 10 to get 8.
6x\geq 6-1.2
Subtract 2 from 8 to get 6.
6x\geq 4.8
Subtract 1.2 from 6 to get 4.8.
x\geq \frac{4.8}{6}
Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.
x\geq \frac{48}{60}
Expand \frac{4.8}{6} by multiplying both numerator and the denominator by 10.
x\geq \frac{4}{5}
Reduce the fraction \frac{48}{60} to lowest terms by extracting and canceling out 12.