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1.04^{2n}=2
Use the rules of exponents and logarithms to solve the equation.
\log(1.04^{2n})=\log(2)
Take the logarithm of both sides of the equation.
2n\log(1.04)=\log(2)
The logarithm of a number raised to a power is the power times the logarithm of the number.
2n=\frac{\log(2)}{\log(1.04)}
Divide both sides by \log(1.04).
2n=\log_{1.04}\left(2\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
n=\frac{\ln(2)}{2\ln(\frac{26}{25})}
Divide both sides by 2.